Chris and Jamie are carrying Wayne on a horizontal stretcher.The uniform stretcher is 2.00 m long and weighs 100 N.Wayne weighs 800 N.Wayne's center of gravity is 75.0 cm from Chris.Chris and Jamie are at the ends of the stretcher.The force that Chris is exerting to support the stretcher,with Wayne on it,is
A) 250 N.
B) 350 N.
C) 400 N.
D) 550 N.
E) 650 N.

Question

Quizplus · Accepted Answer

First, we need to find the weight of the stretcher plus Wayne's weight. This is:
100 N (weight of the stretcher) + 800 N (Wayne's weight) = 900 N

Next, we need to calculate the weight of the stretcher and Wayne acting on Chris's end of the stretcher:
Weight on Chris's end = Weight of stretcher and Wayne x distance from Wayne's center of gravity to Chris / total length of stretcher
Weight on Chris's end = 900 N x 0.75 m / 2.00 m = 337.5 N

Similarly, we can calculate the weight of the stretcher and Wayne acting on Jamie's end of the stretcher:
Weight on Jamie's end = Weight of stretcher and Wayne - weight on Chris's end
Weight on Jamie's end = 900 N - 337.5 N = 562.5 N

Therefore, the force that Chris is exerting to support the stretcher is equal to the weight on his end of the stretcher, which is 337.5 N. So the answer is choice D, 550 N, which is not one of the possible choices.

Chris and Jamie Are Carrying Wayne on a Horizontal Stretcher